Question

Oblicz pH roztworu wodorotlenku sodu o stężeniu 0,0001 mol/dm3

Answer 1

NaOH ---->Na(+) + OH(-)
[NaOH] = [OH-] = 10^-4mol/dm3
pOH = -log[OH-]
pOH = -log10^-4
pOH = 4
pH + pOH = 14
pH = 10