Oblicz steżeni molowe 10% roztworu KOH o gestości 1,19g/dm3.
Cp * d = Cm * M * 100% M= 56g/mol d= 1,19 g/dm3Cp= 10%
10% * 1,19g/dm3 =Cm * 56g/mol * 100% Cm= 10% * 1,19g/dm3 / 56g/mol * 100%Cm= 11,9dm3/ 5600g/mol Cm= 0,002mol/dm3
Pozdrawiam, kate66 ;)
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Cp * d = Cm * M * 100%
M= 56g/mol
d= 1,19 g/dm3
Cp= 10%
10% * 1,19g/dm3 =Cm * 56g/mol * 100%
Cm= 10% * 1,19g/dm3 / 56g/mol * 100%
Cm= 11,9dm3/ 5600g/mol
Cm= 0,002mol/dm3
Pozdrawiam, kate66 ;)