oblicz pHi pOH NaOH o stezeniu 0,001mol/dm3 jesli stopien dysocjai 100%
alfa=1, c=0.001 mol/dm3 x=1x0,001=0.001 czyli stężenie H+ 1x10^-3 pH=3 to pOH=11
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alfa=1, c=0.001 mol/dm3
x=1x0,001=0.001 czyli stężenie H+ 1x10^-3
pH=3 to pOH=11