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C= 1mol/dm3
α= 10% czyli 0,1
α·C= [H+]
[H+]= 1 · 0,1= 0,1 mol/dm3
czyli mamy 0,1 mol jonów H+ bo V= 1dm3
1mol-- 6,02 · 10^ 23 jonów
0,1 mol--- x
x= 6,02 · 10^ 22 jonów H+