2Mg + O2---> 2 MgO
mMg=24 g
mMgO=40 g
A) mMg+mO2=mMgO ( z prawa zachowania masy)
24 g + mO2=40 g
mO2= 16 g
d=m/V
m/d=V
VO2= 16 g/1,31 g/dm3=12,21 dm3
B) mMg:mO=24:16=3:2
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2Mg + O2---> 2 MgO
mMg=24 g
mMgO=40 g
A) mMg+mO2=mMgO ( z prawa zachowania masy)
24 g + mO2=40 g
mO2= 16 g
d=m/V
m/d=V
VO2= 16 g/1,31 g/dm3=12,21 dm3
B) mMg:mO=24:16=3:2