Cn=n/V0,55= n/0,15n=0,0825 mola0,75=0,0825/VV=0,11 dm3 czyli 110 cm3
licze na naj:)
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Cn=n/V
0,55= n/0,15
n=0,0825 mola
0,75=0,0825/V
V=0,11 dm3 czyli 110 cm3
licze na naj:)