Vtlenu = 21%*7m*3m*5m = 0,21*105m³ = 22,05m³ = 22050dm³
m = 1,43g/dm³*22050dm³ = 31531,5g = 31,5315kg
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Vtlenu = 21%*7m*3m*5m = 0,21*105m³ = 22,05m³ = 22050dm³
m = 1,43g/dm³*22050dm³ = 31531,5g = 31,5315kg
21%x7mx3mx5m = 0,21x105m³ = 22,05m³ = 22050dm³
Obliczam masę;
d=m/v
m=dxv
m = 1,43g/dm³*22050dm³ = 31531,5g = 31,5315kg