jaka objętośc roztworu weglanu potasu o stezeniu 2mol/dm³ mozna sporzadzic majac 10g tej soli
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masa molowa: 138g
1 mol - 138g
x mol - 10g
x= 0,07 mol
Cm= n/Vr
Vr= Cm/n
Vr= 2moldm3/0,07 mol
Vr= 28,6dm3