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MC2H5OH=24+5+16+1=46g*2=92g- bo są dwa mole
MCO2=12+32=44*2=88g bo sa dwa mole
92g C2H5OH---------88gCO2
4,6gC2H5OH---------xg
x=4,4g
d=m/v
d*V=m
v=m/d
v=4,4/1.81g/cm3=2,43cm3