January 2019 1 14 Report
Dlaczego dodano 6e oraz 3e?
KMnO _{4} + K _{2} S + H _{2} O --\ \textgreater \ MnO _{2} + SO_{2} + KOH \\ r.utleniania:S ^{2-} + 4OH^{-} --\ \textgreater \ SO_{2} +6e+2H_{2}O \\ r. redukcji: MnO_{4}^{-} +3e+2H_{2}0--\ \textgreater \ MnO_{2}+4OH^{-}
Prosiłabym o wytłumaczenie tego :)
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