Dla kwasu weglowego oblicz : a)stosunek masy pierwiastków, b) masę atomową c)stosunek procentowy pierwiastków
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H₂CO₃
a) H:C:O = 2 x 1: 12: 3 x 16 = 2:12:48 = 1:6:24
b) 2 x 1u + 12u + 3 x 16u = 62u
c)
m H = 2u
%H = 2u/62u x 100% = 3%
mC = 12u
%C = 12u/62u x 100% = 19%
M O = 48u
%O = 48u/62u x 100% = 78%
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