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Segunda:x :12
Tercera:4x :48
3x+4x+x=96
8x=96
x=96/8
x=12
Remplazamos...
B=3x
C=A+B => C=x+3x
x+3x+x+3x= 96
8x= 96
x= 12
Por lo tanto:
A=12
B=36
C=48
Comprobando: 12+36+48=96