Question

Ditunggu jawaban plus caranya
jika Ksp AgI = 10^-16, maka besar kelarutan AgI dalam larutan MgI2 0,005 M adalah...

Answer 1

S=10^-8

(s)(2s+0.01)=
10^-10(2s diabaikan krn kecil)

Answer 2

MgI -> Mg+ + I- (0,005 M)

10^-16 = [Ag+][5x10^-3]
[Ag+] atau s AgI = 10^-16 / 5x10^-3 = 2x10^-14 M

Ksp AgI = [Ag+][I-]