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f(2) = 2²+1=4+1=5
f(3) = 2³+1=8+1=9
f(4) = 2⁴+1=16+1=17
b. f(c) = 2^6+1=64+1=65
nilai c = 6
a. f(1) = 2^1 + 1=2^1=3
f(3) = 2^3 +1 =8+1 =9
f(4) = 2^4 + 1 = 16 +1 =17
b. f(c) = 2^c + 1
65 = 2^c +1
2^c = 64
c= 6