Question

Dimohon bantuannya...
f(x)= ax^3+bx+(a+b) dibagi x^2-3x+2 bersisa (x+1), nilai (a-b) adalah

Answer 1

X² - 3x + 2 = (x - 1)(x - 2)
f(1) = 1 + 1 = 2
maka:
2 = a + b + (a + b)
2a + 2b = 2
a + b = 1

f(2) = 2 + 1 = 3
maka:
3 = 8a + 2b + (a + b)
9a + 3b = 3
3a + b = 1

eliminasi:
3a + b = 1
a + b = 1
________ _
2a = 0
a = 0
b = 1
maka a - b = - 1