Question

Dikumpulin besok., tolong ya no 22-24 ,.

Answer 1

22. a 10
jarak antar pusat^2= (R + r)^2 +garis singgung^2
jp^2= (R+r)^2 + 8^2
jp^2= (2,5+3,5)^2 +64
jp^2= 6^2 + 64
jp^2= 36 =64
jp^2= 100
jp= √100
jp= 10cm
23. c 2:3
24. c 16
singgung luar^2= jp^2 - (R-r)^2
sl^2=20^2 - (14-2)^2
sl^2=400-12^2
sl^2=400-144
sl^2=256
sl=√256
sl= 26 cm