Question

Diketahui=g(x)=3X+1
(g bundaran f) (x)=9xpangkat 2+6x-5
Ditanya=f(x+2)

Answer 1

(g o f)(x)=9x² + 6x - 5
g(x)=3x+1

g(f(x))=9x² + 6x -5
3f(x) + 1 =9x²+ 6x-5
f(x) =3x²+2x-2
f(x+2)=3(x+2)²+2(x+2)-2
f(x+2)= 3x²+14x+14