Diketahui x : y : z = 2 : 6 : 5 dan 4x + 3y - 2z = 80. hitunglah selisih nilai x & z
rhyangrande
X = 2 y = 6 z = 5 Dit : selisih x dan z ? peny nilai x 4x+3y-2z=80 4x+3(6)-2(5)=80 4x+18-10=80 4x+8=80 4x=80-8 4x=72 x=18 nilai z 4x+3y-2z=80 4(2)+3(6)-2z=80 8+18-2z=80 26-2z=80 -2z=80-26 -2z=54 z=-27 selisih x - z = 18-(-27) = 18+27=45
1 votes Thanks 4
sadam991
kok gak ada jawabannya di pilihan ganda ya
y = 6
z = 5
Dit : selisih x dan z ?
peny
nilai x
4x+3y-2z=80
4x+3(6)-2(5)=80
4x+18-10=80
4x+8=80
4x=80-8
4x=72
x=18
nilai z
4x+3y-2z=80
4(2)+3(6)-2z=80
8+18-2z=80
26-2z=80
-2z=80-26
-2z=54
z=-27
selisih
x - z =
18-(-27) =
18+27=45