Jawab:
x-3y-5 = 0 <=> x-3y = 5 ... (1)
gunakan cara eliminasi
x-3y = 5 dikali 2 jadi 2x-6y = 10
2x-6y = 10
2x-5y = 9 -
-------------------
-y = 1
y = -1
substitusi ke (1)
x - 3 x -1 = 5
x = 2
Maka 3x + 2y = 3 x 2 + 2 x (-1) = 4
Diketahui = x - 3y = 5 .....(1)
2x-5y = 9 .....(2)
Ditanya = 3x + 2y =?
Jawab = (Metode Eliminasi)
(1)×2 2x-6y = 10
2x-5y = 9
________ _
(Metode Substitusi)
Substitusikan y ke (2)
2x - 5y = 9
2x + 5 = 9
2x = 4
X = 2
Jadi,
3x + 2y = 6 - 2 = 4
Semoga Membantu
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Jawab:
x-3y-5 = 0 <=> x-3y = 5 ... (1)
gunakan cara eliminasi
x-3y = 5 dikali 2 jadi 2x-6y = 10
2x-6y = 10
2x-5y = 9 -
-------------------
-y = 1
y = -1
substitusi ke (1)
x - 3 x -1 = 5
x = 2
Maka 3x + 2y = 3 x 2 + 2 x (-1) = 4
Diketahui = x - 3y = 5 .....(1)
2x-5y = 9 .....(2)
Ditanya = 3x + 2y =?
Jawab = (Metode Eliminasi)
(1)×2 2x-6y = 10
2x-5y = 9
________ _
-y = 1
y = -1
(Metode Substitusi)
Substitusikan y ke (2)
2x - 5y = 9
2x + 5 = 9
2x = 4
X = 2
Jadi,
3x + 2y = 6 - 2 = 4
Semoga Membantu