Question

Diketahui (x - 3), (x - 1), (2x - 2), dan (2x + 6) membentuk barisan geometri. nilai x + 2 =

Answer 1

Barisan geometri  u1, u2, u3 dan u4

u2² = (u1)(u3)
(x-1)² = (x-3)(2x-2)
x² - 2x + 1 = 2x² - 8x + 6
x² - 6x + 5 = 0
(x - 5)(x -1) = 0
x = 5 atau x = 1
x = 5 --> x + 2 = 7
x = 1 --> x + 2  = 3