Jawaban:
a = 2i + j + 2k
|a| = √(4+1+4)
|a| = √9 = 3
vektor satuan a = a/|a| = (2, 1, 2)/3
= (2/3, 1/3, 2/3)
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Jawaban:
a = 2i + j + 2k
|a| = √(4+1+4)
|a| = √9 = 3
vektor satuan a = a/|a| = (2, 1, 2)/3
= (2/3, 1/3, 2/3)