Question

diketahui titik P (-1,7) dan Q (7,-8). Tentukanra jl LP operasionaljarak titik P dan Q​

Answer 1

Penjelasan dengan langkah-langkah:

PQ=√(7-(-1)²+(-8-7)²

PQ=√(7+1)²+(-15)²

PQ=√8²+225

PQ=√64+225

PQ=√289

PQ=17

Answer 2

•°• Diketahui, titik P (-1,7) dan Q (7,-8),maka jarak titik P dan Q adalah [tex]\underline{\boxed{\red{\bf{17}}}}[/tex]

[tex] \\ \\ [/tex]

Penjelasan dengan langkah-langkah:

• P = [tex]\sf{x_{1}}[/tex] = -1, [tex]\sf{y_{1}}[/tex] = 7
• Q = P = [tex]\sf{x_{2}}[/tex] = 7, [tex]\sf{y_{2}}[/tex] = -8
• Jarak titik P dan Q = ?

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \colorbox{yellow}{ \sf{Jarak titik P dan Q }}[/tex]

[tex]\sf{J_{PQ}}[/tex] = [tex]\sf{\sqrt{(x_{1} - x_{2})² + (y_{1} - y_{2})²}}[/tex]

[tex]\sf{J_{PQ}}[/tex] = [tex]\sf{\sqrt{(-1 - 7)² ( 7 - 8)²}}[/tex]

[tex]\sf{J_{PQ}}[/tex] = [tex]\sf{\sqrt{-8² + (-15)²}}[/tex]

[tex]\sf{J_{PQ}}[/tex] = [tex]\sf{\sqrt{(-8 × (-8)) + (-15 × (-15))}}[/tex]

[tex]\sf{J_{PQ}}[/tex] = [tex]\sf{\sqrt{64 + 225}}[/tex]

[tex]\sf{J_{PQ}}[/tex] = [tex]\sf{\sqrt{289}}[/tex]

[tex]\sf{J_{PQ}}[/tex] = [tex]\sf{\sqrt{17²}}[/tex]

[tex]\sf{J_{PQ}}[/tex] = [tex]\underline{\boxed{\red{\bf{17}}}}[/tex]

[tex] \\ \\ [/tex]

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[tex] \\ \\ \\ \\ \\ \\ \\ \\ [/tex]

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[tex] \: [/tex]

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