Diketahui titik A (3, 0) dan titik B (0, 12) Maka persamaan garis ABnya adalah
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Jawaban:
y2-y1/y-y1 x2-x1/x-x1 12-0/y-00-3/x-3
12x-36=-3y
3y+12x=36
y + 4x = 12
penjelasan:
MAAF Kalau Salah
Jawaban:
y2-y1/y-y1= x2 -x1/x-x1
12-0/y-0=0-3/x-3
12x-36=3y
3y+12x=36
y+4y=12