Penjelasan dengan langkah-langkah:
tan 15° = a/1 → y/x
r = √(x² + y²)
r = √(1² + a²)
r = √(a² + 1)
1] sin 15°
= y/r
= a/√(a² + 1)
= 1/(a² + 1) . (a . √(a² + 1))
2] cos 15°
= x/r
= 1/√(a² + 1)
= 1/(a² + 1) . (√(a² + 1))
3] sin 75°
= sin (90° - 15°)
= cos 15°
Detail jawaban
Kelas 10
Mapel 2 - Matematika
Bab 7 - Trigonometri
Kode Kategorisasi : 10.2.7
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Penjelasan dengan langkah-langkah:
tan 15° = a/1 → y/x
r = √(x² + y²)
r = √(1² + a²)
r = √(a² + 1)
1] sin 15°
= y/r
= a/√(a² + 1)
= 1/(a² + 1) . (a . √(a² + 1))
2] cos 15°
= x/r
= 1/√(a² + 1)
= 1/(a² + 1) . (√(a² + 1))
3] sin 75°
= sin (90° - 15°)
= cos 15°
= 1/√(a² + 1)
= 1/(a² + 1) . (√(a² + 1))
Detail jawaban
Kelas 10
Mapel 2 - Matematika
Bab 7 - Trigonometri
Kode Kategorisasi : 10.2.7