Question

Diketahui suku pertama suatu barisan geometri adalah, dengan m>0. jika suku ke 5 adalah , suku ke-21 barisan tersebut adalah..

Answer 1

A= ∛m = m^(1/3)
u5 = ar^4 = m^2
U5/a = r^4 = m^2 : m^(1/3) = m^( 2-1/3)
r^4 = m^(5/3)
r = m^(5/3 : 4)
r =m^(5/12)
U21 = a. r^20 = m^(1/3) . {m^(5/12}^20
U21 = m^(1/3). m^(25/3)
U21 = m^(1/3+25/3)
U21 = m^(26/3)
u21 = m^8 .m^(2/3) = m^8 . ∛m²