Question

Diketahui sudut A = (3x-10)° dan sudut B = (x-16)° jika sudut A dan sudut B saling berkomplemen maka besar sudut A adlah

Answer 1

Sudut berkomplemen = sudut berpenyiku = A + B = 90°
3x - 10 + x - 16 = 90°
4x - 26 = 90
4x = 90 + 26
x = 116/4
x = 29
besar sudut A = 3x - 10 = (3 x 29) - 10 = 87 - 10 = 77°

Answer 2

Saling berkomplemen, jumlahnya = 90

90 = <A + <B
90 = 3x - 10 + x - 16
90 = 4x - 26
90+26 = 4x
116 = 4x
29= x

<A = 3x - 10 = 3(29) - 10 = 87 - 10 = 77 derajat