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Verified answer
K. persegi = K. persegi panjang4 x s = 2p + 2l
4(x+3) =2(2x-3) + 2(x+1)
4x+12 = 4x-6 + 2x+2
a. persamaan:
4x - 4x - 2x= -6+2-12
-2x= -16
x= -16/-2=8
nilai x=8
b. panjang sisi persegi=x+3=8+3=11 cm
smoga membantu
= 4(x+3)
= 4x +12
k persegi panjang= 2p +. 2l
4x+12 = 2(2x-3)+2(x+1)
4x+12 = 4x-6+2x+2
4x-4x-2x=-6-12+2
-2x = -16
x = -16/-2
x =8
a. x=8 cm
b. panjang sisi persegi = x +3
= 8 +3 = 11 cm