f(3)=3
3a+b=3
f(1)=-1
a+b=-1
2a=4
a=2
2+b=-1
b=-1-2
b=-3
2(m+1)+(-3)
2m+2-3
=2m-1
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f(3)=3
3a+b=3
f(1)=-1
a+b=-1
3a+b=3
a+b=-1
2a=4
a=2
2+b=-1
b=-1-2
b=-3
2(m+1)+(-3)
2m+2-3
=2m-1