Question

Diketahui sistem persamaan 3x+2y=8 dan x-5y+37=0. nilai 6x+4y adalah...

Answer 1

* 3x + 2y = 8 |x(dikali)5|
  x - 5y =  -37 |x2|     
  15x +10y = 40
  2x - 10y = -74     +
  17x     = -34
   x = -34/17 
   x = -2
* x - 5y = -37
  -2 - 5y = -37
   -5y = -37 +2
  - 5y = -35
  y = -35/-5
  y = 7
* nilai 6x + 4y
 = 6(-2) + 4(7)
 = -12 + 28
 = 16