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y₂ = x² + nx + 1
y₁ = y₂
-2x -3 = x²+nx+1
0= x²+ (n-2)x +4
- 2 penyelesaian artinya discriminan > 0
d = b²-4ac
d = (n-2)² - 4(1)(4)
d = (n²-4n+4)-16
d= n²-4n-12
d > 0
n²-4n-12>0
(n-6)(n+2)>0
maka, n>6 dan n<-2