Diketahui sin x + cos x = 1 dan tan x = 1, tentukan nilai sin x dan cos x
alvinteguh
Tan x = 1 sin x + cos x = 1 bagi kedua ruas dengan cos x sin x/cos x + cos x/cos x = 1/cos x tan x + 1 = sec x 1 + 1 = sec x 2 = sec x 2 = 1/cos x cos x = 1/2
sin x = √(1 - cos²x) = √(1 - (1/2)²) = √(1 - 1/4) = √(3/4) = 1/2 √3
sin x + cos x = 1
bagi kedua ruas dengan cos x
sin x/cos x + cos x/cos x = 1/cos x
tan x + 1 = sec x
1 + 1 = sec x
2 = sec x
2 = 1/cos x
cos x = 1/2
sin x = √(1 - cos²x)
= √(1 - (1/2)²)
= √(1 - 1/4)
= √(3/4)
= 1/2 √3
depan/samping = 1
depan = samping
depan/miring + samping/miring = 1
2depan/miring = 1
2depan = miring
depan = miring/2
misal, depan = 1
depan = miring/2
2depan = miring
miring = 2
sinx = depan/miring
= 1/2
samping = √(2² - 1²)
= √3
cosx = √3/2