Question

Diketahui segitiga siku siku ABC. AB= 4√3, AC= 4√2. BC=………

Answer 1

BCkuadrat= (4/2)kuadrat + (4/3)kuadrat
= (16x2) + (16x3)
= 32+48
=80
BC= /80
=/16.5
=4/5

Simbol "/" anggap aja akar ya :)
Smga mmbntu :)