PEMBAHASAN
Pythagoras
Segitiga
∆ABC siku di B
AB = 16 cm
AC = 20 cm
AB² + BC² = AC²
Panjang sisi BC
= √(AC² - AB²)
= √(20² - 16²)
= √(20 + 16) × √(20 - 16)
= √36 × √4
= 6 × 2
= 12 cm
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Verified answer
PEMBAHASAN
Pythagoras
Segitiga
∆ABC siku di B
AB = 16 cm
AC = 20 cm
AB² + BC² = AC²
Panjang sisi BC
= √(AC² - AB²)
= √(20² - 16²)
= √(20 + 16) × √(20 - 16)
= √36 × √4
= 6 × 2
= 12 cm