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=> (x+1+3x-4).(4x-8)/2 < 42
=> (4x-3).(2x-4) < 42
=> 8x^2-16x-6x+12 < 42
=> 8x^2-22x+12-42 < 0
=> 8x^2-22x-30 < 0 (kedua ruas dibagi 2)
=> 4x^2-11x-15 < 0
=> 1/4.(4x-15).(4x+4) < 0 (difaktorkan)
=> (4x-15)(x+1) < 0
=> 4x=15, x=15/4 atau => x=-1
itu jawabannya
maaf kalo salah, masih coba2 sih :D