Question

Diketahui sebuah balok memiliki perbandingan p:l:t = 4:2:3 jika luas permukaan balok 1.300cm². hitunglah ukura panjang, lebar, dan tinggi balok

Answer 1

Lp = 2 (pxl + pxt + lxt)
1300/2 = (4x.2x + 4x.3x + 3x.2x)
650 = (8x^ + 12x^ + 6x^)
650 = 26x^
650/26 = x^
√25 = x
5 = x
p = 4 . 5 = 20 cm
l = 2 . 5 = 10 cm
t = 3 .5 = 15 cm

Answer 2

Lp = (2xpxl) + (2xpxt) + (2xlxt)
1300 = (2x4ax2a) + (2x4ax3a) + (2x2ax3a)
1300 = 16a² + 24a² + 12a²
1300 = 52a²
a² = 25
a = 5

Maka;
p = 4a = 4(5) = 20 cm
l = 2a = 2(5) = 10 cm
t = 3a = 3(5) = 15 cm