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R(-2)=a.(-2)+b=-4
=-2a+b=-4...(i)
R(-6)=a.(-6)+b=12
=-6a+b=12...(ii)
eliminasi: -2a+b=-4 b.-2a+b=-4
-6a+b=12 -2(-4)+b=-4
----------------- - b=-4-8
4a=-16 = -12
a=-4
b. R(x)=ax+b
R(x)=-4x-12
c. R(25)=-4(25)-12
R(25)=-100-12
= -112
-2a + b = -4
dari r(-6) = 12 didapat
-6a + b = 12
kemudian dieliminasi (dikurangin) sehingg didapat
4a = -16
a = -4
kemudian subtitusi a kemana saja
-2a + b = -4
-2 x -4 + b = -4
8 + b = -4
b = -12