Question

Diketahui rumus suatu fungsi f(X)=AX+B dan f(3)=5 dan f(-1)=-3. nilai f(4) adalah...........

Answer 1

A(3)+b = 5
a(-1) + b -3
dikurang
2a = 2
a = 1


1(3)+b=5
3 + b = 5
b = 5-3
b = 2

f(4) = 1 (4) + 2
=4+2 = 6

Answer 2

A(3)+B=5 A(-1)+B=(-3) dikurang 4A=8 A=2 3A+B=5 3(2)+B=5 6+B=5 B= -1 F(4)=AX+B =2(4)+(-1) =8+(-1) =7