Diketahui rumus fungsi f(x)=(x+a)+3 dan f(2)=7. tentukan a.Nilai f(-1) b.Nilai f(-2) + f(-1) c.Bentuk fungsi f(2x -- 5)
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*) f(2)= 7
=> (2+a)+3 = 7
=> 2+a = 7-3
2+ a = 4
a = 4-2
a = 2
jdi f(x) = (x+a)+3
f(x) = (x+2)+3
a) f(-1) = (-1+2)+3
= 1+3 = 4
b) f(-2) + f(-1) = ((-2+2)+3)+4
= 3+4
= 7
c) f(2x-5) => ((2x-5)+2)+3
= (4x-10)+3