Diketahui rumus fungsi f(x)=3x-4, jika nilai f(2a+1)=11 maka nilai f(8-a) adalah.... Question from @ArulABz

October 2018 2 136 Report

Diketahui rumus fungsi f(x)=3x-4, jika nilai f(2a+1)=11 maka nilai f(8-a) adalah..

dnnyz07 F(2a+1) = 3(2a+1) - 4
6a +3-4 = 11
6a -1 = 11
6a = 12
a = 2
nilai f(8-a)
8-2 = 6
f(6) = 3(6)-4
=18-4
=14

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dnnyz07 14

izharulhaq78 $f(x)=3x-4\\\\f(2a+1)=3(2a+1)-4\\11=6a+3-4\\11=6a-1\\11+1=6a\\12=6a\\2=a\\\\f(8-a)=f(8-2)=f(6)\\f(6)=3(6)-4\\f(6)=18-4\\f(6)=14$

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