Question

Diketahui rumus fungsi f(x)=2ax+b. Jika f(3)=15 dan f(-2)=10. Tentukan:
a. Nilai a dan b
b. Rumus fungsi f(x)
c. Nilai f(6)

Answer 1

F(3) = 2a(3) + b = 15
= 6a + b = 15
f(-2) = 2a(-2) + b = 10
= -4a + b = 10
= 10a = 5
a = 1/2
= -4(1/2) + b = 10
-2 + b = 10
b = 10+2
= 12

B. f(x) = 2(1/2)x + 12
= x+12
C. f(6) = 6+12
= 18