Question

Diketahui rumus fungsi f(x) = a.x + b , jika f(-3) = 9 dan f(2) = 11, maka nilai a + b adalah...

Answer 1

F(-3) = a.-3 + b = 9 -3a + b = 9 (persamaan 1) F(2) = a.2 + b = 11 2a + b = 11 ( persamaan 2) Lalu persmaan 1 dan 2 di eliminasi Dengan hasil nilai a = 2/5 Nilai b = 51/5 Jadi a+b= 53/5 = 10.6

Answer 2

F(x)=ax+b
f(-3)= -3a+b
f(2) = 2a+b

-3a+b=9
 2a+b=11

-5a= -2
a=2/5

2.2/5+b=11
4/5+b=11
b=11-4/5
b=51/5

a+b
=2/5+51/5
=53/5


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