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t = 24 cm
r = 7 cm
π = 22/7
Jawab :
s² = t² + r²
= 24² + 7²
= 576 + 49
s² = 625
s = √625
s = 25
l. selimut = πrs
= 22/7 x 7 x 25
= 550 cm² (B)
=7²+24²
=49+576
=624
s =25
luas selimut kerucut = πrs
=22/7 x 7 x 25
=550