gradien 2 titik (-3,-5)&(-2,-8)
m1 = y2-y1 / x2-x1 = -8+5/-2+3 = -3
gradien tegak lurus
m1*m2 = -1
m2 = -1/-3 = 1/3
persamaan garis melalui titik (-2,4)
y-y1 = m(x-x1)
y-4 = 1/3 (x+2)
----------------------- x 3
3y-12 = x+2
3y-x-14 = 0
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gradien 2 titik (-3,-5)&(-2,-8)
m1 = y2-y1 / x2-x1 = -8+5/-2+3 = -3
gradien tegak lurus
m1*m2 = -1
m2 = -1/-3 = 1/3
persamaan garis melalui titik (-2,4)
y-y1 = m(x-x1)
y-4 = 1/3 (x+2)
----------------------- x 3
3y-12 = x+2
3y-x-14 = 0