Diketahui matriks A = ![\left[\begin{array}{cc}2&-3\\x&-2\\\end{array}\right]](https://tex.z-dn.net/?f=+%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-3%5C%5Cx%26-2%5C%5C%5Cend%7Barray%7D%5Cright%5D+ "\left[\begin{array}{cc}2&-3\\x&-2\\\end{array}\right]")
meiliki invers matriks 
dan nilai det( ) = 2 , tentukan nilai x
tifianti
![(A^{-1} ) = \left[\begin{array}{ccc}2&-3\\x&-2&\\\end{array}\right] \\ -2 = ad-bc \\ -2 = 2(-2)-(-3)(x) \\ -2= -4 + 3x \\ 3x = 4 + 2 \\ 3x = 6 \\ x= \frac{6}{3} \\ x = 2](https://tex.z-dn.net/?f=%28A%5E%7B-1%7D+%29+%3D+++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-3%5C%5Cx%26-2%26%5C%5C%5Cend%7Barray%7D%5Cright%5D++%5C%5C+-2+%3D+ad-bc+%5C%5C+-2+%3D+2%28-2%29-%28-3%29%28x%29+%5C%5C+-2%3D+-4+%2B+3x+%5C%5C+3x+%3D+4+%2B+2+%5C%5C+3x+%3D+6+%5C%5C+x%3D+%5Cfrac%7B6%7D%7B3%7D+%5C%5C+x+%3D+2+ "(A^{-1} ) = \left[\begin{array}{ccc}2&-3\\x&-2&\\\end{array}\right] \\ -2 = ad-bc \\ -2 = 2(-2)-(-3)(x) \\ -2= -4 + 3x \\ 3x = 4 + 2 \\ 3x = 6 \\ x= \frac{6}{3} \\ x = 2")
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