Question

Diketahui log 2 -> 0,3010; log 3-> 0,4771; dan log 5-> 0,6989. tentukan:
1. log 0,6
2. log 60
3. log 135
4. log 0,45

Answer 1

1. Log 0,6 = log (6/10) = log (2x3/10) = log 2 + log 3 - log 10 = 0,3010 + 0,4771 - 1 = -0,2219

2. Log 60 = log (2x3x10) = log 2 + log 3 + log 10 = 0,3010 + 0,4771 + 1 = 1,7781

3. Log 135 = log (5x27) = log (5x3^3) = log 5 + log 3^3 = log 5 + 3 x log 3 = 0,6989 + 3 x 0,4771 = 0,6989 + 1,4313 = 2,1302

4. Log 0,45 = log (5x3^2/10^2) = log 5 + log 3² - log 10² = log 5 + 2 x log 3 - 2 x log 10 = 0,6989 + 2 x 0,4771 + 2 x 1 = 0,6989 + 0,9542 + 2 = 3,6531

#cuma ngsih tau.  ^  ---> maksudnya pangkat#