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AB² + AD² = BD² ⇒ AB = AD
2 AB² = (12√2)²
2 AB² = 288
AB ² = 144
AB = 12 cm
Next, mencari tinggi Δ TBC = √[TO² + (1/2AB²)]
= √(8² + 6²)
= √(64 + 36)
= √100
= 10 cm
a). Luas Δ TBC = 1/2 x alas x tinggi
= 1/2 x 12 x 10
= 60 cm²
next, cari luas alas limas = AB x BC ⇒ AB = BC = CD = DA = 10 cm
= 10 x 10
= 100 cm²
b). Volume limas T.ABCD = 1/3 x luas alas x tinggi
= 1/3 x 100 x 8
= 266,67 cm³