Limas
AB = 20 cm
BC = 16 cm
Q tengah AD
P tengah BC
O tengah PQ
Perhatikan segtiga PTO dan PQT
∠PTO = ∠QTO = a
BD = √(AB² + AD²) = 4√41 cm
TO = √(TB² - OB²) = √(17² - (2√41)²) = 5√5 cm
tan a = PO/TO = 10/5√2 = √2
sudut antara TAD dan TBC = sudut PTQ = 2 × sudut PTO = 2a
tan 2a
= 2 tan a / (1 - tan² a)
= 2√2 / (1 - 2)
= -2√2 ✔
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Limas
AB = 20 cm
BC = 16 cm
Q tengah AD
P tengah BC
O tengah PQ
Perhatikan segtiga PTO dan PQT
∠PTO = ∠QTO = a
BD = √(AB² + AD²) = 4√41 cm
TO = √(TB² - OB²) = √(17² - (2√41)²) = 5√5 cm
tan a = PO/TO = 10/5√2 = √2
sudut antara TAD dan TBC = sudut PTQ = 2 × sudut PTO = 2a
tan 2a
= 2 tan a / (1 - tan² a)
= 2√2 / (1 - 2)
= -2√2 ✔