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AC = 4 CT = AT = 6
BC' = x, maka TC' = 6 - x
t² = CT² - (6-x)² , t² = AC² - x²
CT² - (6-x)² = AC² - x²
36 - (36 - 12x + x²) = (4)² - x²
12 x - x² = 32 - x²
x =
t = =
alas = ABCD, dengan sisi = 4
tinggi = T
TA = 6 cm
(C,TA) =?
jawab :
misalkan titik tengah TA = E
jadi, AE = TE = 3
AC =
=
=
=
CE =
=
=
=
jadi, jarak C ke TA atau (C,TA) =
semoga membantu :) jadikan yang terbaik ya :))