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Verified answer
Kubus ABCD.EFGHrusuk = a cm
∆BDG samasisi
P tengah BD
CP = 1/2 . AC
CP = 1/2 . a√2 cm
ѳ = sudut antara CG dan bidang BDG
tan ѳ = CP/CG
tan ѳ = 1/2 a√2 /a = 1/2 √2
ѳ = 45°