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HC = √10²+10² = 10√2
1/2 HC = 10√2 : 2 = 5√2
AD = 10
1/2 AD = 5
jarak M ke HC = √(1/2 AD)² + (1/2 HC)²
√ (5)² + (5√2)²
√ 25 + 25.2
√ 25 + 50
√75 = 5√3